LESSON PLAN Using the algebra, equations, linear inequalities in one variable and solving problems comparison

LESSON PLAN

                   Educational Unit             :            Junior High School

                   Subject                            :            Mathematics

                   Grade                              :            VIII

                   Competency Standard    :            Using the algebra, equations, linear inequalities in one variable and solving problems comparison

                   Basic Competence          :            Using the concepts of algebra in solving social problems as simple arithmetic

                   Time Allocation              :    2 x 40 minutes

                   Meeting                           :    1

A.      1.  Indicators

Simulate the social arithmetic of everyday economic activities.

2.  Learning

     Students can use algebraic concepts in solving social problems as simple arithmetic.

B.       Resources

1.      Student Book

2.      Students Worksheet

C.      Activities

1.      Teaching Model         : STAD (Student Teams Achivement Division)

2.      Methods                     : Discussion

              I.      Introduction

a.       Remind student the previous lesson about the

b.      Motivate the importance of mastering this material well, to assist students in understanding the use of social arithmetical in economic activity.

c.       Inform indicators of learning achievement and the teaching model that will be used in learning, direct intruction.

d.      Teacher divided student into a heterogeneous group of students and mix on presentation, gender, ethnicity, religion, race and other factors every group consisiting of 4 student. (phase 1)

          II.      Main Activity

a.       Eksplain about the social solving problem simple arithmetical.

Overall value, Unit value, Many units, a gain or profit, lose, Percentage profit, Percentage loss, Rebates or discounts, Gross.

(phase 2).

b.      Give the student the example of using the concepts of algebra in solving social problems as simple arithmetic.

Ø  Current gasoline prices rose to Rp4.500, 00 @ liters. A seller of gasoline still has a supply of 50 liters, which bought the old price Rp2.400, 00 @ liters. Gasoline is selling at a price he Rp5.000, 00 @liters. How much profit from the sale of gasoline?

Ø  Answer:

purchase price = Rp2.400, 00 X 50 = Rp 120.000,00

selling price = Rp5.000, 00 X 50 = Rp 250.000,00

profit = selling price - purchase price

          = Rp 250.000,00 - 120.000,00

           = Rp 130.000,00

So the profit was Rp 130.000,00       

c.       Ask the students to do the exercises in the worksheet 1.1 in pairs.

For the groups who have completed the exercise, so some one of the group members presented the result of this work to all other members of the group, until they are understand. (phase 3)

d.      Ask the student to do exercises 1.2 individually and when answered should should not help each other. (phase 4)

e.       The teaher gives evaluation for the exercises (phase 5)

 III.            Closing

a.       Guide student to make a summary of the learning materials they have studied. (phase 6)

b.      The teacher give homework to the student in exercises 1.3 and ask to the student to study the next chapter about algebraic concepts in solving social problems as simple arithmetic.

D.       Evaluation

a.                Type of assessment                       :           Written test

b.               Form assessment               :           Individually and group test

c.                Example of assessment     :          

1.         One dozen pencils purchased at a priceRp18.000, -. If then the pencilRp18.000, -. If then the pencilresold at a priceresold at a price Rp 2,000, - per stem, then great Rp 2,000, - per stem, then greatprofit derived entirelyprofit derived entirelyis ...

Student book

ALGEBRAIC CONCEPTS IN SOLVING SOCIAL PROBLEMS AS SIMPLE ARITHMETIC.

1.      PROFIT / INCOME

Profit / Profit: occurs because the selling price is greater than the purchase price (capital) of the purchase price (capital)
profit conditions are: price> purchase price.

2.        PROFIT = SELLING PRICE - PURCHASE PRICE
% Profit = (profit: The purchase price) x 100%
% U = (U: B) x 100%

3.      LOSS
Loss occurs if the selling price <  purchase price (capital),
terms of loss of the selling price <  purchase price

4.      LOSS = SALE PRICE - PURCHASE PRICE
% Loss = (Loss: Hg. Purchase) x 100%
% R = (R: B) x 100%

5.      PRICE AND PRICE BUY

Ø   Selling price:
Selling price = purchase price + profit
Selling price = purchase price – loss

Ø   The purchase price
The purchase price = selling price - profit
The purchase price = selling price + loss

1.      Student worksheet 1.1

Group :                                                                                             Class:

 Answer the question!

1.            A merchant bought 24 kg orange for Rp 150.000, -.orange for Rp 150.000, -.He sold half the price. He sold half the priceRp 9,000, -/kg, he sold one-thirdRp 9,000, -/kg, he sold one-thirdthe price of Rp 7,500, -/kg, andthe price of Rp 7,500, -/kg, and the rest he sold at a price of Rpthe rest he sold at a price of Rp
6000, -/kg.if all the oranges sold out, thenevents that will be experienced traders is ...

2.            A merchant bought a some  toys for Rp 280,000, -. Because toys for Rp 280,000, -. Because most of the toy is faulty thenmost of the toy is faulty then every toy he sold for Rp every toy he sold for Rp 10 500, -. Thus traders 10 500, -. Thus traders will experience ...

Key of worksheet 1.1

1.            Selling price:

Ø  Pjln I: ½ x 24 x Rp 9,000, - = Rp108 000,-
Pjln II: 1 /3 x 24 x Rp7.500, - = Rp 60.000, -

Ø  Remainder = 24 - 12 - 8 = 4 kg
Pjln  III: 4 x Rp 6,000, - = Rp 24,000, -

Ø  Total sales = Rp 192,000, -

Ø  Since the sale> purchase the trader profits.

Ø  Big profit = sales - buy
= Rp 192,000 - Rp 150,000
= Rp 42,000, -

2.            Big profit = Selling - Buying
= Rp 1.95 million - Rp 1,500,000
= Rp 450.000,

Ø  % Profit = profit / purchase price x 100%
= Rp 450.000/Rp 1.5 million x 100%
= 30%

Exercises 1.2

1. A tape recorder purchased at a price Rp 200,000.00. The selling price of a tape recorder The lucky 35% that is
2. A bag is sold at Rp230.000, 00 was already memberikan untung 15
   %. The purchase price of the bag tersebut adalah

Key of exercises 1.2

1. Profit = 35% of the price of the bell
   = 35/100 x Rp 200,000.00 = Rp 70000.00
   Selling price = purchase price + profit
   = Rp 200.000, - + Rp 70.000, - = Rp 270,000, -
2. Selling price = Rp 230,000, -
   Profit = 15%.
   Selling price = 115%.
   The purchase price = (100: 115) x Rp 230,000) x Rp 230,000 = Rp 200,000.00